[TRNSYS-users] Receiver azimuth ? Type 34 Overhang and Wingwall Shading

[David BRADLEY via TRNSYS-users]

Yossef,

   If you define the Type34 "receiver azimuth" parameter using an 
equation that references the "turn" variable then it can be 
automatically set. If you leave the Type34 parameter set to zero then 
that means that Type34 thinks that the receiver (window) faces the equator.

kind regards,

  David



On 03/21/2017 12:39, Yossef Ibrahimi wrote:
> Dear all,
>
> I'm simulating a building with shaded windows using Type 34 (Overhang 
> and Wingwall Shading), I don't understand the parameter "Receiver 
> azimuth".
> I've already run a simulation for a south oriented window, now I'm 
> willing to modifiy the orientation of the building using the TURN 
> parameter, shall I modify this "Receiver azimuth" according to the 
> angle used in the TURN parameter ? or should it be 0 ?
>
> Thank you
> Regards,
> Yossef

-- 
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David BRADLEY
Principal
Thermal Energy Systems Specialists, LLC
22 North Carroll Street - suite 370
Madison, WI  53703 USA

P:+1.608.274.2577
F:+1.608.278.1475
d.bradley at tess-inc.com

http://www.tess-inc.com
http://www.trnsys.com

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