[TRNSYS-users] Question about H2 electrolyzer Type 160

David BRADLEY d.bradley at tess-inc.com
Thu Nov 20 12:54:07 PST 2014


Sunliang,
   In the Type160 code, the equation for the heat generated by the 
electrolyzer is qGen = nCells*Iely*(Vcell-Vtn)

where Iely is the electrolyzer current, Vcell is the cell voltage and 
Vtn is the thermoneutral cell voltage. The Faraday efficiency is 
computed from:

eta_f = idensity**2/(a1+idensity**2)*a2

where idensity is the current density of the cells (Iely/Acell)

I think that both the Faraday efficiency and the heat generated are a 
result of the computation of the cell voltage and the stack current. 
Therefore I think that the heat generation is correctly computed and 
that the confusion may be in the definition of the energy efficiency and 
the total energy efficiency.
Kind regards,
  David



On 11/20/2014 07:36, SUNLIANG CAO wrote:
> Dear all,
>
> I have a question about the H2 electrolyzer model Type160. Shortly: 
> Will the Faraday loss of the electrolyzer be converted into heat in 
> the electrolyzer?
>
> In the electrolyzer model (Type 160 written by Ulleberg) [1], there 
> are three efficiencies: eta_e, eta_F, and eta_tot:
>
> "eta_e" is the energy efficiency of electrolyzer without considering 
> any Faraday loss, i.e. the maximum theoretical proportion of the 
> electricity which can be covered to the hydrogen energy content.
>
> "eta_F" is the Faraday efficiency: it is the ratio of the real final 
> produced H2 energy content to the theoretical maximum produced H2 
> energy content.
>
> "eta_tot" is the total efficiency of the electrolyzer: it is equal to 
> "eta_e*eta_F", and thus is the ratio of the final produced H2 energy 
> content to the electricity consumed in the electrolyzer.
>
> In Ullerberg's model [1] (TRNSYS Type 160), the heating generated by 
> the electrolyzer is calculated by the P_ely*(1-eta_e), which hasn't 
> taken the Faraday loss into account. However, according to the energy 
> balance, the Faraday loss must be somewhere, which mostly in the form 
> of heat, so I doubt why the Faraday loss hasn't been taken into 
> account in the thermal part of the electrolyzer model.
>
> Reference [1]: Øystein Ulleberg, Modeling of advanced alkaline 
> electrolyzers: a system simulation approach, International Journal of 
> Hydrogen Energy, Volume 28, Issue 1, January 2003, Pages 21-33. 
> http://www.sciencedirect.com/science/article/pii/S0360319902000332# 
> <http://www.sciencedirect.com/science/article/pii/S0360319902000332>
>
> Thank you very much.
>
> Kind Regards,
>
> Sunliang Cao
>
>
>
>
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> TRNSYS-users at lists.onebuilding.org
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-- 
***************************
David BRADLEY
Principal
Thermal Energy Systems Specialists, LLC
22 North Carroll Street - suite 370
Madison, WI  53703 USA

P:+1.608.274.2577
F:+1.608.278.1475
d.bradley at tess-inc.com

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