[TRNSYS-users] Definition of Type 34 Receiver
Rudai Shan
rdshan at umich.edu
Mon Jun 24 21:35:21 PDT 2013
Dear All Trnsys users,
I'm doing simulation for a window with grid shading. The height of the
window is 1.2 m and the width of the window is 1.8 m. The grid shading
divided the window into 8 parts, each part is 0.45 m width and 0.6 m
height. The depth of the shading is 0.1 m. In type 56 I could only input
the window area. In type 34 I can input the projection of the overhang and
fin, both are 0.1 m. I think the receiver means the window area for each
divided part in my case, so I input 0.45 m for the width and 0.6 m for the
height. Could anybody tell me this is correct or wrong?
Thank you for your time and attention.
Best regards,
Rudai Shan
PhD student,
TCAUP, University of Michigan
-------------- next part --------------
An HTML attachment was scrubbed...
URL: <http://lists.onebuilding.org/pipermail/trnsys-users-onebuilding.org/attachments/20130625/8e8c5c60/attachment-0004.htm>
More information about the TRNSYS-users
mailing list