[TRNSYS-users] KWh /m2 / year

[David BRADLEY]

Alex,
   I would use an integrator component (Type24) to integrate the energy 
use over the entire year, then pass its output to an equation that 
divides by 3600 (to get kWh) and by 330 (to get energy per m2.)
Best,
  David


On 3/28/2012 04:49, Alex Rachid wrote:
>
> Hi All,
>
> I am simulating a Cooling System:TYP92 with TYPE56
>
> I stored the energy removed in KWh in an excel sheet for every hour 
> (simulation step)
>
> QCool in KWh =QCool KJ/h/3600
>
> how do I calculate using the output I am attaching the cooling energy 
> in : KWh /m2/year
>
> Cooled area: 330 m2
>
> (what happens if the simulation step is 0.5 hr instead of 1 hour)
>
> Thanks in advance..
>
> Regards
>
> Alex
>
>
>
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-- 
***************************
David BRADLEY
Principal
Thermal Energy Systems Specialists, LLC
22 North Carroll Street - suite 370
Madison, WI  53703 USA

P:+1.608.274.2577
F:+1.608.278.1475
d.bradley at tess-inc.com

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