[TRNSYS-users] Type 56 Thermo Active Layer Resistances

[Devin Rohan]

In the Type 56 manual, it models the thermal network from the supply water
to the pipe plane node as resistances placed in series.  For example, if I
wanted to find the rate of heat transfer from one node to the next, by
using...

Q=[ A*(T1-T2) ] / R

What area would I use, since all the resistance values are in units of
[m^2-K/W].  Here's what I was thinking...

*Rz*: thermal resistance in z-direction along the pipe length--> A=area of
the floor surface, since I see the mean temperature as being similar to node
k (pipe plane temperature ) and the heat transfer goes up through the floor
into the space.

*Rw: *thermal resistance by forced convection (from fluid to pipe shell) for
cylindrical areas--> A=2*pi*Ri*L, the inside surface area of the pipe

*Rr:* thermal resistance by conduction through the pipe shell--> A=[pi*Ro^2]
- [pi*Ri^2], where Ro and Ri are the outside and inside pipe radii

*Rx:* thermal resistance from outer pipe shell to pipe plane by
conduction--> A= floor thickness (since the heat transfer is horizontal)

Please let me know if this is incorrect.  Thank you

-- 
Devin M. Rohan
drohan at purdue.edu
-------------- next part --------------
An HTML attachment was scrubbed...
URL: <http://lists.onebuilding.org/pipermail/trnsys-users-onebuilding.org/attachments/20110504/0610d0a6/attachment-0005.htm>