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</o:shapelayout></xml><![endif]--></head><body lang=DE link=blue vlink=purple><div class=WordSection1><p class=MsoNormal><span lang=EN-US style='mso-fareast-language:DE'>Dear Trnsys-Experts,<o:p></o:p></span></p><p class=MsoNormal><span lang=EN-US style='mso-fareast-language:DE'><o:p> </o:p></span></p><p class=MsoNormal><span lang=EN-US style='mso-fareast-language:DE'>Would anyone one happen to have an experience on calculating their own data file for a single effect water fired absorption chiller (Type 107)<o:p></o:p></span></p><p class=MsoNormal><span lang=EN-US style='mso-fareast-language:DE'>I am wondering if anybody have done a scheme on Excel-Spreadsheet or something like that. I’m trying to make one and wondering if it is dependable or not.<o:p></o:p></span></p><p class=MsoNormal><span lang=EN-US style='mso-fareast-language:DE'>I also got confused on the documents supplied and hoped that someone could help me clarify.<o:p></o:p></span></p><p class=MsoNormal><span lang=EN-US style='mso-fareast-language:DE'><o:p> </o:p></span></p><p class=MsoNormal><span lang=EN-US style='mso-fareast-language:DE'>So first I calculated the “Cooling Power Required for the Rated Temperature” with “mDot_CHW*Cp_CHW*(T_CHW_In-T_CHW_Out)”<o:p></o:p></span></p><p class=MsoNormal><span lang=EN-US style='mso-fareast-language:DE'>And then I read from the diagram supplied by the company (PDF-File Page 8, pardon the German language) the “Multipliers” on capacity rated and multiply it with the “Rated Capacity”, resulting the “Available Cooling Capacity” [Repeat for each Temperature].<o:p></o:p></span></p><p class=MsoNormal><span lang=EN-US style='mso-fareast-language:DE'>Divide the resulting “Available Cooling Capacities” with the “Cooling Power Required for the Rated Temperature” give me the “Fraction of Capacity” i.e. the first required row for the data file. <o:p></o:p></span></p><p class=MsoNormal><span lang=EN-US style='mso-fareast-language:DE'>(Is this correct?)<o:p></o:p></span></p><p class=MsoNormal><span lang=EN-US style='mso-fareast-language:DE'><o:p> </o:p></span></p><p class=MsoNormal><span lang=EN-US style='mso-fareast-language:DE'>For the “Fraction of Design energy input” I first calculated the “Heating Power Resulted from the Rated Temperature” using “mDot_HW*Cp_HW*(T_HW_In-T_HW_Out)”.<o:p></o:p></span></p><p class=MsoNormal><span lang=EN-US style='mso-fareast-language:DE'>And read the diagrams (page 7) for the “Heat Input” (cooling mode) on different Hot water temperature. I then divide the “Heat Input” by the “Heating Power Resulted from the Rated Temperature” resulting the “Fraction of Design Energy Input” <o:p></o:p></span></p><p class=MsoNormal><span lang=EN-US style='mso-fareast-language:DE'>(Is this also correct?)<o:p></o:p></span></p><p class=MsoNormal><span lang=EN-US style='mso-fareast-language:DE'><o:p> </o:p></span></p><p class=MsoNormal><span lang=EN-US style='mso-fareast-language:DE'>Lastly, I’m wondering on how to get the “Fraction of design Load”?<o:p></o:p></span></p><p class=MsoNormal><span lang=EN-US style='mso-fareast-language:DE'>Or maybe my approach is completely wrong?<o:p></o:p></span></p><p class=MsoNormal><span lang=EN-US style='mso-fareast-language:DE'><o:p> </o:p></span></p><p class=MsoNormal><span lang=EN-US style='mso-fareast-language:DE'>Any comments, algorithms or examples for any other chillers would be very helpful, I’m absolutely confused right now.<o:p></o:p></span></p><p class=MsoNormal><span lang=EN-US style='color:#1F497D'><o:p> </o:p></span></p><p class=MsoNormal><span lang=EN-US>Thanks in advance.<o:p></o:p></span></p><p class=MsoNormal><span lang=EN-US><o:p> </o:p></span></p><p class=MsoNormal><span lang=EN-US>Best regards,<o:p></o:p></span></p><p class=MsoNormal><span lang=EN-US style='mso-fareast-language:DE'><o:p> </o:p></span></p><p class=MsoNormal><span style='color:#7F7F7F;mso-fareast-language:DE'>--------------------------------------------------------------------------------<o:p></o:p></span></p><p class=MsoNormal><span style='color:#7F7F7F;mso-fareast-language:DE'>Yose Wandy B.Sc.<o:p></o:p></span></p><p class=MsoNormal><span style='color:#7F7F7F;mso-fareast-language:DE'>Wissenschaftlicher Mitarbeiter<o:p></o:p></span></p><p class=MsoNormal><span style='color:#7F7F7F;mso-fareast-language:DE'><o:p> </o:p></span></p><p class=MsoNormal><span style='color:#1F497D;mso-fareast-language:DE'><img width=38 height=38 id="Bild_x0020_1" src="cid:image001.jpg@01D0EB06.4DDE4D90" alt="Beschreibung: nur_logo_klein"></span><b><span style='color:#7F7F7F;mso-fareast-language:DE'>Ostfalia Hochschule für angewandte Wissenschaften</span></b><span style='color:#7F7F7F;mso-fareast-language:DE'><o:p></o:p></span></p><p class=MsoNormal><span style='color:#7F7F7F;mso-fareast-language:DE'>Hochschule Braunschweig/Wolfenbüttel<o:p></o:p></span></p><p class=MsoNormal><span style='color:#7F7F7F;mso-fareast-language:DE'>Fakultät Versorgungstechnik<o:p></o:p></span></p><p class=MsoNormal><span style='color:#7F7F7F;mso-fareast-language:DE'>Institut für energieoptimierte Systeme (EOS)<o:p></o:p></span></p><p class=MsoNormal style='line-height:13.05pt'><span style='color:#7F7F7F;mso-fareast-language:DE'>Prof. Dr.-Ing. Lars Kühl<o:p></o:p></span></p><p class=MsoNormal><span style='color:#7F7F7F;mso-fareast-language:DE'><o:p> </o:p></span></p><p class=MsoNormal><span style='color:#7F7F7F;mso-fareast-language:DE'>Salzdahlumer Straße 46-48<o:p></o:p></span></p><p class=MsoNormal><span style='color:#7F7F7F;mso-fareast-language:DE'>D - 38302 Wolfenbüttel<o:p></o:p></span></p><p class=MsoNormal><span style='color:#7F7F7F;mso-fareast-language:DE'><o:p> </o:p></span></p><p class=MsoNormal><span style='color:#7F7F7F;mso-fareast-language:DE'><a href="http://www.ostfalia.de/v">www.ostfalia.de/v</a><o:p></o:p></span></p><p class=MsoNormal><span style='color:#7F7F7F;mso-fareast-language:DE'><o:p> </o:p></span></p><p class=MsoNormal><span lang=EN-US style='color:#7F7F7F;mso-fareast-language:DE'>Tel. 0049 - 5331 / 939 – 40 550<o:p></o:p></span></p><p class=MsoNormal><span lang=EN-US style='color:#7F7F7F;mso-fareast-language:DE'>Fax 0049 - 5331 / 939 – 40 552<o:p></o:p></span></p><p class=MsoNormal><u><span lang=EN-US style='color:blue;mso-fareast-language:DE'><a href="mailto:y.wandy@ostfalia.de">y.wandy@ostfalia.de</a></span></u><span lang=EN-US style='color:#7F7F7F;mso-fareast-language:DE'><o:p></o:p></span></p><p class=MsoNormal><span lang=EN-US><o:p> </o:p></span></p></div></body></html>