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Martin,<br>
One convenient way of defining the solar fraction is: <br>
<br>
qDelivered/(qAux + qParasitics)<br>
<br>
qDelivered would come from your adsorption chiller model, qAux would
be the amount of energy delivered by the aux heater, and qParasitics
would primarily be your pumping energy and the electricity required
by the adsorption chiller. This method avoids having to worry at all
about what is happening in the tank.<br>
Kind regards,<br>
David<br>
<br>
<br>
<div class="moz-cite-prefix">On 5/3/2014 05:23, Martin Berov wrote:<br>
</div>
<blockquote
cite="mid:CAJam3+WEg7Zu5OxOUjrpULX+UPWW85d5TQd3Xr2j5oRR5qCUog@mail.gmail.com"
type="cite">
<div dir="ltr">Hi to all,
<div><br>
</div>
<div>I need opinion about a calculation: I have a tank Type 60
which is heated with solar collectors(heat exchanger) and it's
outlet is in serial connected to auxiliary heater used to
drive adsorption chiller. The return of the chiller is sent
either in the tank or again directly to the aux.heater
depending from the temperature etc...</div>
<div>Since I want to calculate the solar fraction I need the
amount of energy removed from the tank so do you think than I
only need the output "Energy removed from the outlet" or I
need the difference between the "Energy removed from the
outlet - Energy supplied from the inlet" - since if I use this
difference I never reach the required heat energy - For
example having adsorption chiller with 5 kW cooling power even
with aux heater of 30 kW and flow rate of 5000 kg/h I have hot
energy lower than the required? </div>
<div>I also use the heat, cooling and chilled energy in the
control strategy</div>
<div><br>
</div>
<div>What do you think?</div>
<div><br>
</div>
<div>Kind regards</div>
<div>Martin</div>
<div><br>
</div>
</div>
<br>
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Principal
Thermal Energy Systems Specialists, LLC
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