<p><br>Dear all,</p>
<p> Happy new year!</p>
<p> I have a question about calculating total heating demand:</p>
<p>There is one same room to keep indoor temperature as 20°C one day 24 hours, the initial indoor temperature is 20°C, there is no infiltration no other internal gains in the room. I used 3 different methods to calculate total heating demand of one day, separately.</p>
<p>1.First is heating in TRNBuild: after using the INTEGRATOR TYPE 46, the QHEAT is about 34314 kJ.</p>
<p>2.Second is floor heating(active layer): after using the INTEGRATOR TYPE 46, the QALFL_Inlet is about 33680.7kJ.</p>
<p>3.Third is still floor heating(active layer): after using the INTEGRATOR TYPE 46, but I used Q=CwaterMwater(Tinlet-Toutlet), the result of Q is 144639kJ.</p>
<p>My question is: 1) To 2 and 3: Why is the difference is so large? 3 is almost 4 times than 3? I will get the total heating demand, which one is right? Why? What's different of both of them?</p>
<p>2) If 3 is right. Generally, the floor heating should be more energy-saving than common heating. But here result is absolutely opposite. The common heating is more energy-heating. Why? Here what difference of common heating and floor heating?</p>
<p>Many thanks!</p>
<p>Br.</p>
<p>wang<br></p>
<div class="gmail_quote">在 2011年1月5日 下午7:55，王洋 <span dir="ltr"><<a href="mailto:wanghongyang1767@gmail.com">wanghongyang1767@gmail.com</a>></span>写道：<br>
<blockquote style="BORDER-LEFT: #ccc 1px solid; MARGIN: 0px 0px 0px 0.8ex; PADDING-LEFT: 1ex" class="gmail_quote">
<div class="im">Dear all,<br><br> Happy new year!<br><br> I have a question about calculating total heating demand:<br><br>There is one same room to keep indoor temperature as 20°C one day 24 hours, the initial indoor temperature is 20°C, there is no infiltration no other internal gains in the room. I used 3 different methods to calculate total heating demand of one day, separately.<br>
<br>1.First is heating in TRNBuild: after using the INTEGRATOR TYPE 46, the QHEAT is about 34314 kJ.<br><br>2.Second is floor heating(active layer): after using the INTEGRATOR TYPE 46, the QALFL_Inlet is about 33680.7kJ.<br>
<br>3.Third is still floor heating(active layer): after using the INTEGRATOR TYPE 46, but I used Q=CwaterMwater(Tinlet-Toutlet), the result of Q is 144639kJ.<br><br>My question is: 1) To 2 and 3: Why is the difference is so large? 3 is almost 4 times than 3? I will get the total heating demand, which one is right? Why? What's different of both of them?<br>
<br>2) If 3 is right. Generally, the floor heating should be more energy-saving than common heating. But here result is absolutely opposite. The common heating is more energy-heating. Why? Here what difference of common heating and floor heating?<br>
<br>Many thanks!<br><br>Br.<br><br>wang<br><br><br></div>
<div class="gmail_quote">在 2011年1月5日 下午2:38，王洋 <span dir="ltr"><<a href="mailto:wanghongyang1767@gmail.com" target="_blank">wanghongyang1767@gmail.com</a>></span>写道：
<div>
<div></div>
<div class="h5"><br>
<blockquote style="BORDER-LEFT: #ccc 1px solid; MARGIN: 0px 0px 0px 0.8ex; PADDING-LEFT: 1ex" class="gmail_quote">Dear all,<br><br> Happy new year!<br><br> I have a question about calculating total heating demand:<br><br>
There is one same room to keep indoor temperature as 20°C one day 24 hours, the initial indoor temperature is 20°C, there is no infiltration no other internal gains in the room. I used 3 different methods to calculate total heating demand of one day, separately.<br>
<br>1.First is heating in TRNBuild: after using the INTEGRATOR TYPE 46, the QHEAT is about 34314 kJ.<br><br>2.Second is floor heating(active layer): after using the INTEGRATOR TYPE 46, the QALFL_Inlet is about 33680.7kJ.<br>
<br>3.Third is still floor heating(active layer): after using the INTEGRATOR TYPE 46, but I used Q=CwaterMwater(Tinlet-Toutlet), the result of Q is 144639kJ.<br><br>My question is: 1) To 2 and 3: Why is the difference is so large? 3 is almost 4 times than 3? I will get the total heating demand, which one is right? Why? What's different of both of them?<br>
<br>2) If 3 is right. Generally, the floor heating should be more energy-saving than common heating. But here result is absolutely opposite. The common heating is more energy-heating. Why? Here what difference of common heating and floor heating?<br>
<br>Many thanks!<br><br>Br.<br><br>wang<br><br><br><br>
<div class="gmail_quote">2011/1/4 <span dir="ltr"><<a href="mailto:trnsys-users-request@cae.wisc.edu" target="_blank">trnsys-users-request@cae.wisc.edu</a>></span><br>
<blockquote style="BORDER-LEFT: rgb(204,204,204) 1px solid; MARGIN: 0pt 0pt 0pt 0.8ex; PADDING-LEFT: 1ex" class="gmail_quote">Send TRNSYS-users mailing list submissions to<br> <a href="mailto:trnsys-users@cae.wisc.edu" target="_blank">trnsys-users@cae.wisc.edu</a><br>
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<br>When replying, please edit your Subject line so it is more specific<br>than "Re: Contents of TRNSYS-users digest..."<br><br>Today's Topics:<br><br> 1. optimization problems using trnopt in Windows 7 OS (Dapeng Li)<br>
<br><br>---------- 已转发邮件 ----------<br>From: Dapeng Li <<a href="mailto:jiap1120@gmail.com" target="_blank">jiap1120@gmail.com</a>><br>To: <a href="mailto:TRNSYS-users@cae.wisc.edu" target="_blank">TRNSYS-users@cae.wisc.edu</a><br>
Date: Tue, 4 Jan 2011 18:00:38 +0100<br>Subject: [TRNSYS-users] optimization problems using trnopt in Windows 7 OS<br>Dear all,
<div><br></div>
<div>I want to do optimization using trnsys, trnopt and genopt in<b> Windows 7 OS. </b>But when I run the example in the directory of "C:\Program Files\Trnsys16_1\Optimization", I got a error message in Genopt interface that is enclosed in the attachment. </div>
<div><br></div>
<div>The version I use is listed below: TRNSYS version 16.01.0003, trnopt version 2.1.0.52, genopt version 2.1.0 June 18, 2008.</div>
<div><br></div>
<div>PS: I ever did optimization in XP OS, and it work well. </div>
<div><br></div>
<div>Thanks in advance.</div>
<div><br></div>
<div>With kind regards,</div>
<div><br></div>
<div>Dapeng Li</div>
<div><br></div>
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