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John,<br>
Most of the building models in TRNSYS simply ask for the user to
supply the external heat transfer coefficient so you can treat it however
you like. The algorithm that I usually use is from ASRHAE:<br><br>
h = (AA+BB*WindVel+CC*WindVel**2)*3.6<br><br>
where h is the external convection coefficient in kJ/h.m2, AA, BB, and CC
are empirical coefficients that depend on the exterior surface material
and WindVel is the wind speed in m/s. The AA, BB and CC coefficients
(again from ASHRAE) would be:<br><br>
<x-tab> </x-tab><x-tab>
</x-tab><x-tab>
</x-tab>AA<x-tab>
</x-tab>BB<x-tab>
</x-tab>CC<br>
Stucco<x-tab> </x-tab><x-tab>
</x-tab>11.58<x-tab>
</x-tab>5.894<x-tab> </x-tab>0.0<br>
Brick<x-tab> </x-tab><x-tab>
</x-tab><x-tab>
</x-tab>12.49<x-tab>
</x-tab>4.065<x-tab> </x-tab>0.028<br>
Concrete<x-tab> </x-tab>
<x-tab> </x-tab>
10.79<x-tab> </x-tab>4.192<x-tab>
</x-tab>0.0<br>
Wood<x-tab> </x-tab><x-tab>
</x-tab><x-tab>
</x-tab>8.23<x-tab>
</x-tab>4.00<x-tab>
</x-tab>-0.057<br>
Smooth
plaster<x-tab> </x-tab>10.22<x-tab> </x-tab>
3.1<x-tab> </x-tab>0.0<br>
Glass<x-tab> </x-tab><x-tab>
</x-tab><x-tab>
</x-tab>8.23<x-tab>
</x-tab>3.33<x-tab>
</x-tab>-0.036<br><br>
Cheers,<br>
David<br><br>
<br>
At 13:30 9/12/2007, J.A. Palyvos wrote:<br>
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boundary="----=_NextPart_000_0010_01C7F584.16361600"<br>
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Dear all,<br>
<br>
I would appreciate any information on the external forced convection
algorithms (i.e. <u>wind loss coefficient</u> expressions) used in
TRNSYS.(I am aware of the McAdams/Jurges linear relation used in Type
19).<br>
<br>
Many thanks,<br>
<br>
J.A. Palyvos, NTUA<br>
Athens<br>
<br>
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