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Thanks Bishop!!</div>
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Yes <span style="font-size:11.0pt; font-family:"Calibri",sans-serif">SHW heater </span>
<span style="font-size:11.0pt; font-family:"Calibri",sans-serif">¡Â24 amps  but voltage range is 380 </span><span style="font-size:11.0pt; font-family:"Calibri",sans-serif"> volts.
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<span style="font-size:11.0pt; font-family:"Calibri",sans-serif">4kW is circulation pump.
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<span style="font-size:11.0pt; font-family:"Calibri",sans-serif">Thanks for your suggestion.
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<div style="font-size:13.3333339691162px"><span style="font-size:10pt">Warm Regards </span></div>
<div style="font-size:12.8000001907349px"><font color="#000000"><span style="font-size:13.3333330154419px">Harshal Gupta</span></font></div>
<font color="#073763"><b>Energy Analyst</b></font></div>
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<div id="divRplyFwdMsg" dir="ltr"><font style="font-size:11pt" face="Calibri, sans-serif" color="#000000"><b>From:</b> Bishop, Bill <bbishop@pathfinder-ea.com><br>
<b>Sent:</b> 05 December 2018 22:35<br>
<b>To:</b> Harshal Gupta<br>
<b>Cc:</b> equest-users@lists.onebuilding.org<br>
<b>Subject:</b> RE: ASHRAE baseline EF for service hot water heater</font>
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<span style="font-size:11.0pt; font-family:"Calibri",sans-serif">Hi Harshal,</span></p>
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<span style="font-size:11.0pt; font-family:"Calibri",sans-serif">Is your project¡¯s SHW heater
</span><span style="font-size:11.0pt; font-family:"Calibri",sans-serif">¡Â24 amps and</span><span style="font-size:11.0pt; font-family:"Calibri",sans-serif">
</span><span style="font-size:11.0pt; font-family:"Calibri",sans-serif">¡Â250 volts? Based on the storage capacity, I¡¯m guessing it¡¯s much larger, in which case the formula you shared doesn¡¯t apply.</span></p>
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<span style="font-size:11.0pt; font-family:"Calibri",sans-serif">I¡¯m also guessing that the 2000 L storage tank is not an integral part of the heat pump and that the 4 kW circulation pump serves a supply/return loop from the heat pump to the storage tank. I
 believe that would make it an ¡°Unfired storage tank¡± per the referenced Table 7.8, with minimum performance of R12.5 tank insulation.</span></p>
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<span style="font-size:11.0pt; font-family:"Calibri",sans-serif">Lastly, I¡¯m not aware of a direct formula for converting from energy factor (EF) to COP. However, I think EF and COP should be comparable (close to the same number), and not the inverse of each
 other. If you did in fact have a water heater with 0.233 EF, the COP would definitely be way less than 1.</span></p>
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<span style="font-size:11.0pt; font-family:"Calibri",sans-serif">I suggest you check the heat pump manufacturer¡¯s literature to see how it was rated. There may not be a formal test procedure applicable to the heater and it is probably not covered in the ASHRAE
 90.1 tables. If that is the case, you will need to determine a non-ASHRAE method to determine savings.</span></p>
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<span style="font-size:11.0pt; font-family:"Calibri",sans-serif">Regards,</span></p>
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<span style="font-size:11.0pt; font-family:"Calibri",sans-serif">~Bill</span></p>
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<b><span style="font-size:10.0pt; font-family:"Franklin Gothic Medium",sans-serif; color:black">William Bishop, PE, BEMP, BEAP, CEM, LEED AP</span></b></p>
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<b><span style="font-size:11.0pt; font-family:"Calibri",sans-serif">From:</span></b><span style="font-size:11.0pt; font-family:"Calibri",sans-serif"> Equest-users <equest-users-bounces@lists.onebuilding.org>
<b>On Behalf Of </b>Harshal Gupta via Equest-users<br>
<b>Sent:</b> Tuesday, December 4, 2018 3:24 AM<br>
<b>To:</b> equest-users@lists.onebuilding.org<br>
<b>Subject:</b> [Equest-users] ASHRAE baseline EF for service hot water heater</span></p>
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<span style="font-size:10.0pt; font-family:"Arial",sans-serif; color:#006FC9">Hello All,</span><span style="font-size:10.0pt; font-family:"Arial",sans-serif">                                                                                                                                                                                
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<b><u><span style="font-size:14.0pt; font-family:"Arial",sans-serif; color:#006FC9">Project Details
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<span style="font-size:10.0pt; font-family:"Arial",sans-serif; color:#006FC9">I have an issue for conversion of EF to COP of service hot water heater.</span></p>
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<span style="font-size:10.0pt; font-family:"Arial",sans-serif; color:#006FC9">Their is a service hot water heater installed in my project of 2000 L or 528 US gallons capacity. Heater is equipped with a re circulation pump of 4kW.</span></p>
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<b><u><span style="font-size:14.0pt; font-family:"Arial",sans-serif; color:#006FC9">Modeling Issue
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<span style="font-size:10.0pt; font-family:"Arial",sans-serif; color:#006FC9">As per ASHRAE 90.1 base case the minimum efficiency to be considered in base case as per table 7.8. Minimum efficiency  formula as per table is 0.93-.00132 ¡îV EF.
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<span style="font-size:10.0pt; font-family:"Arial",sans-serif; color:#006FC9">With the above formula considering V as 528 US gallons Energy Factor (EF) will be 0.233. In many articles it was marked COP is 1/EF, by this statement COP will be 4.299.
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<span style="font-size:10.0pt; font-family:"Arial",sans-serif; color:#006FC9">This is giving me the negative savings.</span></p>
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<span style="font-size:10.0pt; font-family:"Arial",sans-serif; color:#006FC9">Can any one help me with correct process for conversion of EF to COP.
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<span style="font-size:10.0pt; font-family:"Arial",sans-serif; color:#006FC9">Secondly, what should be pump power in base case?</span></p>
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<b><span style="font-size:10.0pt; font-family:"Arial",sans-serif; color:#006FC9">Thanks in Advance
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