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Thanks for your response.</div>
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As per ASHRAE 90.1 : 2010 appendix G electric resistant based water heater to be model and sized according to section 7.4.1.
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In base case and efficiency of electric heater should be considered as per table 7.4.2.
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In my project the capacity of heat pump based SWH is as follows:</div>
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Rated heating capacity : 19.8kW</li><li style="font-family: arial, helvetica, sans-serif; font-size: 10pt; color: rgb(0, 111, 201); background-color: rgba(0, 0, 0, 0);">
Rated power input : 6.02 kW</li><li style="font-family: arial, helvetica, sans-serif; font-size: 10pt; color: rgb(0, 111, 201); background-color: rgba(0, 0, 0, 0);">
Maximum power input : 6.8kW</li></ol>
As per table 7.8 performance required for resistance based electric should be 0.93-0.00132 V EF, which is again 0.233 EF.
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In modeling tool eQUEST, EIR is required which is ratio of electric input power to nominal heater capacity.
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EF is a combination of thermal efficiency and standby losses, in case if i modeled tank losses as 0 by putting Tank UA =0 in DWH in eQUEST. What should i model in EIR?</div>
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<span style="font-size: 14pt; line-height: normal;">Please someone guide can guide on this.</span><br>
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<div style="font-size:13.3333339691162px"><span style="font-size:10pt">Warm Regards </span></div>
<div style="font-size:12.8000001907349px"><font color="#000000"><span style="font-size:13.3333330154419px">Harshal Gupta</span></font></div>
<font color="#073763"><b>Energy Analyst</b></font></div>
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<div id="divRplyFwdMsg" dir="ltr"><font style="font-size:11pt" face="Calibri, sans-serif" color="#000000"><b>From:</b> David Eldridge <DEldridge@grummanbutkus.com><br>
<b>Sent:</b> 05 December 2018 01:10<br>
<b>To:</b> Harshal Gupta<br>
<b>Subject:</b> RE: ASHRAE baseline EF for service hot water heater</font>
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<span style="font-size:11.0pt; font-family:"Calibri",sans-serif; color:#1F497D">I don¡¦t want to post to the list since this isn¡¦t my main expertise. But EF includes the value of the insulation of the tank as well as cycling losses, so 1/EF can¡¦t be the COP
exactly, since it includes tank losses it won¡¦t be the reciprocal of compressor efficiency.</span></p>
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<span style="font-size:11.0pt; font-family:"Calibri",sans-serif; color:#1F497D">You would be modeling the losses explicitly in the modeling program, correct? So you just want the actual heat pump system COP.</span></p>
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<span style="font-size:11.0pt; font-family:"Calibri",sans-serif; color:#1F497D">I think EF is proportional to COP though, not inverse ¡V i.e. higher EF is better and higher COP is also better. Gas storage systems have EF less than one, and sometimes much less
than one¡Ka heat pump could be above 1.0, but I don¡¦t have a great feel for it ¡V my expectation might be more in the 2.0 range than 4.0 but that¡¦s a gut feeling.</span></p>
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<span style="font-size:11.0pt; font-family:"Calibri",sans-serif; color:#1F497D"><a href="https://www.energy.gov/energysaver/estimating-costs-and-efficiency-storage-demand-and-heat-pump-water-heaters">https://www.energy.gov/energysaver/estimating-costs-and-efficiency-storage-demand-and-heat-pump-water-heaters</a></span></p>
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<span style="font-size:11.0pt; font-family:"Calibri",sans-serif; color:#1F497D"> </span></p>
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<span style="font-size:11.0pt; font-family:"Calibri",sans-serif; color:#1F497D">Not sure about the pump ¡V if the recirculation is the same in both cases, model it identically. I don¡¦t believe it is meant to be built into the EF, and I also don¡¦t know of any
other W/gpm requirement for them¡Kcheck the rest of the service hot water section for any pump power requirements that I might be forgetting.</span></p>
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<span style="font-size:11.0pt; font-family:"Calibri",sans-serif; color:#1F497D">David</span></p>
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<span style="font-size:8.0pt; font-family:"Calibri",sans-serif; color:black"> </span><span style="font-size:11.0pt; font-family:"Calibri",sans-serif; color:#1F497D"></span></p>
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<span style="font-size:11.0pt; font-family:"Calibri",sans-serif; color:#1F497D">David S. Eldridge, Jr., P.E., LEED AP BD+C, BEMP, BEAP, HBDP</span><span style="font-size:11.0pt; font-family:"Calibri",sans-serif; color:#1F497D"></span></p>
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<b><span style="font-size:11.0pt; font-family:"Calibri",sans-serif; color:#244061">Grumman/Butkus Associates</span></b><span style="font-size:11.0pt; font-family:"Calibri",sans-serif; color:#1F497D"></span></p>
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<b><span style="font-size:11.0pt; font-family:"Calibri",sans-serif">From:</span></b><span style="font-size:11.0pt; font-family:"Calibri",sans-serif"> Equest-users [mailto:equest-users-bounces@lists.onebuilding.org]
<b>On Behalf Of </b>Harshal Gupta via Equest-users<br>
<b>Sent:</b> Tuesday, December 04, 2018 2:24 AM<br>
<b>To:</b> equest-users@lists.onebuilding.org<br>
<b>Subject:</b> [Equest-users] ASHRAE baseline EF for service hot water heater</span></p>
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<span style="font-size:10.0pt; font-family:"Arial",sans-serif; color:#006FC9">Hello All,</span></p>
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<b><u><span style="font-size:14.0pt; font-family:"Arial",sans-serif; color:#006FC9">Project Details
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<span style="font-size:10.0pt; font-family:"Arial",sans-serif; color:#006FC9">I have an issue for conversion of EF to COP of service hot water heater.</span></p>
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<span style="font-size:10.0pt; font-family:"Arial",sans-serif; color:#006FC9">Their is a service hot water heater installed in my project of 2000 L or 528 US gallons capacity. Heater is equipped with a re circulation pump of 4kW.</span></p>
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<b><u><span style="font-size:14.0pt; font-family:"Arial",sans-serif; color:#006FC9">Modeling Issue
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<span style="font-size:10.0pt; font-family:"Arial",sans-serif; color:#006FC9">As per ASHRAE 90.1 base case the minimum efficiency to be considered in base case as per table 7.8. Minimum efficiency formula as per table is 0.93-.00132 ¡ÔV EF.
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<span style="font-size:10.0pt; font-family:"Arial",sans-serif; color:#006FC9">With the above formula considering V as 528 US gallons Energy Factor (EF) will be 0.233. In many articles it was marked COP is 1/EF, by this statement COP will be 4.299.
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<span style="font-size:10.0pt; font-family:"Arial",sans-serif; color:#006FC9">This is giving me the negative savings.</span></p>
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<span style="font-size:10.0pt; font-family:"Arial",sans-serif; color:#006FC9">Can any one help me with correct process for conversion of EF to COP.
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<span style="font-size:10.0pt; font-family:"Arial",sans-serif; color:#006FC9">Secondly, what should be pump power in base case?</span></p>
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<b><span style="font-size:10.0pt; font-family:"Arial",sans-serif; color:#006FC9">Thanks in Advance
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