<div dir="ltr"><div><p class="MsoNormal"><span style="color:rgb(33,88,104)">Hi Vishal,<span></span></span></p>
<p class="MsoNormal"><span style="color:rgb(33,88,104)"> </span></p><p class="MsoNormal"><span style="color:rgb(33,88,104)"><br></span></p>
<p class="MsoNormal"><span style="color:rgb(33,88,104)">As per my understanding you will have to account with the
Loop Design Delta T losses for getting the result.<span></span></span></p>
<p class="MsoNormal"><span style="color:rgb(33,88,104)">The Case that I am taking is having a Loop Design Delta-T
of 10 degree Fahrenheit which is as follows as an example of Loop Design
Delta-T.<span></span></span></p>
<p class="MsoNormal"><span style="color:rgb(33,88,104)"> </span></p>
<p class="MsoNormal"></p><div><img src="cid:ii_jko1uq5w3_165241b00825625f" width="369" height="278"><br></div><br><p></p>
<p class="MsoNormal"><span style="color:rgb(33,88,104)"> </span></p>
<p class="MsoNormal"><span style="color:rgb(33,88,104)">So the changes that you are required to have is the 5%
losses in the loop Delta-T design which has to be taken as 0.5 degree
Fahrenheit in the Supply Loss DT. The change that you are required to do is in
the cooling circulation loop in the losses tab which is as follows:<span></span></span></p>
<p class="MsoNormal"><br></p><p class="MsoNormal"></p><div><img src="cid:ii_jko1tz0q2_165241a777a01945" width="367" height="276"><br></div><br><p></p>
<p class="MsoNormal"><span style="color:rgb(33,88,104)"> </span></p>
<p class="MsoNormal"><span style="color:rgb(33,88,104)">For Heating the Design Delta-T in my case is 40 degree Fahrenheit
which is given as below:<span></span></span></p>
<p class="MsoNormal"><br></p><p class="MsoNormal"></p><div><img src="cid:ii_jko1t77y1_1652419edc1741d0" width="367" height="276"><br></div><br><p></p>
<p class="MsoNormal"><span style="color:rgb(33,88,104)">The assumed changes required to be done is to change the
Looses Delta-T for heating in the heating circulation loop. The required loss
is 10%, hence the loop Design Delta-T losses is 4 degree Fahrenheit has to be
taken:<span></span></span></p>
<p class="MsoNormal"><br></p><p class="MsoNormal"></p><div><img src="cid:ii_jko1sgv50_165241964c87f576" width="366" height="276"><br></div><br><p></p>
<p class="MsoNormal"><span style="color:rgb(33,88,104)"> </span></p>
<p class="MsoNormal"><span style="color:rgb(33,88,104)">With the help of these two changes in the Cooling and
Heating Circulation loop in the losses tab one can achieve the percentage
losses as required by the reviewer.<span></span></span></p>
<p class="MsoNormal"><span style="color:rgb(33,88,104)"> </span></p>
<p class="MsoNormal"><span style="color:rgb(33,88,104)"> </span></p>
<p class="MsoNormal"><b><span style="color:rgb(33,88,104)">Thanks,<span></span></span></b></p>
<p class="MsoNormal"><span style="color:rgb(33,88,104)">Sharad.Kumar.<span></span></span></p>
<p class="MsoNormal"><span style="color:rgb(33,88,104)">+91-9102906597<span></span></span></p>
<p class="MsoNormal"><span style="color:rgb(33,88,104)">Freelancer (Energy Simulation)<span></span></span></p>
<p class="MsoNormal"><span style="color:rgb(33,88,104)">India.<span></span></span></p><p class="MsoNormal"><span style="color:rgb(33,88,104)"><br></span></p><p class="MsoNormal"><span style="color:rgb(33,88,104)">.........................................................................................................................................</span></p></div><div><br></div><div>---------- Forwarded message ----------<br>From: equest user <<a href="mailto:equestuser00@gmail.com">equestuser00@gmail.com</a>><br>To: <a href="mailto:equest-users@lists.onebuilding.org">equest-users@lists.onebuilding.org</a><br>Cc: <br>Bcc: <br>Date: Thu, 9 Aug 2018 15:26:17 +0530<br>Subject: [Equest-users] Modelling losses in chillers<br><div dir="ltr"><p class="MsoNormal" style="margin:0in 0in 0.0001pt;text-align:justify;line-height:normal;font-size:11pt;font-family:Calibri,sans-serif"><span style="font-size:12pt;color:rgb(37,64,97)">Hola Modelers,</span></p><p class="MsoNormal" style="margin:0in 0in 0.0001pt;text-align:justify;line-height:normal;font-size:11pt;font-family:Calibri,sans-serif"><span style="font-size:12pt;color:rgb(37,64,97)"> </span></p><p class="MsoNormal" style="margin:0in 0in 0.0001pt;text-align:justify;line-height:normal;font-size:11pt;font-family:Calibri,sans-serif"><span style="font-size:12pt;color:rgb(37,64,97)">Its time that I need some help!!</span></p><p class="MsoNormal" style="margin:0in 0in 0.0001pt;text-align:justify;line-height:normal;font-size:11pt;font-family:Calibri,sans-serif"><br></p><p class="MsoNormal" style="margin:0in 0in 0.0001pt;text-align:justify;line-height:normal;font-size:11pt;font-family:Calibri,sans-serif"><span style="font-size:12pt;color:rgb(37,64,97)">My building includes chilled water district cooling system in which I have received a review comment which is as follows:</span></p><p class="MsoNormal" style="margin:0in 0in 0.0001pt;text-align:justify;line-height:normal;font-size:11pt;font-family:Calibri,sans-serif"><span style="font-size:12pt;color:rgb(37,64,97)"> </span></p><p class="MsoNormal" style="margin:0in 0in 0.0001pt;text-align:justify;line-height:normal;font-size:11pt;font-family:Calibri,sans-serif"><i><span style="font-size:12pt;color:rgb(37,64,97)">“If following Option 2 of the district thermal guidelines the Proposed model must reflect a virtual plant with the same average efficiencies of the entire upstream district energy system based on actual loading (average efficiencies can be determined using either the Monitoring or Modeling methods described in Appendix C). Alternatively, the default plant efficiency values outlined in Section 2.4.1.2.3 of the guidelines (4.4 COP for DES cooling plant and 70% for DES heating plant) may be may be used to reflect the district energy plants in the Proposed model</span></i><i><span style="font-size:12pt;color:red">. In addition, thermal distribution losses must be accounted for in the Proposed model based on the losses determined in the actual design or the default values outlined in Section 2.4.1.2.3 of the guidelines may be used (5% for chilled water district cooling, 10% for hot water district heating, 15% for closed steam loop, or 25% for open steam loop)</span></i><i><span style="font-size:12pt;color:rgb(37,64,97)">”</span></i><i><span style="font-size:12pt;color:red"></span></i></p><p class="MsoNormal" style="margin:0in 0in 0.0001pt;text-align:justify;line-height:normal;font-size:11pt;font-family:Calibri,sans-serif"><i><span style="font-size:12pt;color:red"> </span></i></p><p class="MsoNormal" style="margin:0in 0in 0.0001pt;text-align:justify;line-height:normal;font-size:11pt;font-family:Calibri,sans-serif"><span style="font-size:12pt;color:rgb(37,64,97)">Can anyone help me on how should I account 5 % losses mentioned in the comment (highlighted in red)?? </span></p><p class="MsoNormal" style="margin:0in 0in 0.0001pt;text-align:justify;line-height:normal;font-size:11pt;font-family:Calibri,sans-serif"><span style="font-size:12pt;color:red"> </span></p><p class="MsoNormal" style="margin:0in 0in 0.0001pt;text-align:justify;line-height:normal;font-size:11pt;font-family:Calibri,sans-serif"><span style="font-size:12pt;color:rgb(37,64,97)">Waiting for the reply.</span></p><p class="MsoNormal" style="margin:0in 0in 0.0001pt;text-align:justify;line-height:normal;font-size:11pt;font-family:Calibri,sans-serif"><span style="font-size:12pt;color:rgb(37,64,97)"> </span></p><p class="MsoNormal" style="margin:0in 0in 0.0001pt;text-align:justify;line-height:normal;font-size:11pt;font-family:Calibri,sans-serif"><span style="font-size:12pt;color:rgb(37,64,97)">Thanks</span></p><p class="MsoNormal" style="margin:0in 0in 0.0001pt;text-align:justify;line-height:normal;font-size:11pt;font-family:Calibri,sans-serif"><span style="font-size:12pt;color:rgb(37,64,97)">Vishal</span></p><div><span style="font-size:12pt;color:rgb(37,64,97)"><br></span></div></div></div></div>