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<p class=MsoNormal><span style='color:navy;font-weight:normal'>Dear all,<o:p></o:p></span></p>
<p class=MsoNormal><span style='color:navy;font-weight:normal'><o:p> </o:p></span></p>
<p class=MsoNormal><span style='color:navy;font-weight:normal'>I am simulating
a building (LEED NC v2.2) in a campus with centralized cooling / heating
system.<o:p></o:p></span></p>
<p class=MsoNormal><span style='color:navy;font-weight:normal'>As according to “Treatment
of district or campus thermal energy in LEED v2 & LEED 2009”, a
virtual plant with default efficiency can be used.<o:p></o:p></span></p>
<p class=MsoNormal><span style='color:navy;font-weight:normal'>There are few
questions regarding the COP as well as the thermal loss:<o:p></o:p></span></p>
<p class=MsoNormal><span style='color:navy;font-weight:normal'><o:p> </o:p></span></p>
<p class=MsoListParagraph style='text-indent:-18.0pt;mso-list:l0 level1 lfo1'><![if !supportLists]><span
style='color:navy;font-weight:normal'><span style='mso-list:Ignore'>a)<span
style='font:7.0pt "Times New Roman"'> </span></span></span><![endif]><span
style='color:navy;font-weight:normal'>The COP of cooling plant shall be 4.4
including cooling towers and primary pumps.<o:p></o:p></span></p>
<p class=MsoListParagraph><span style='color:navy;font-weight:normal'>Does it
mean that chillers, cooling towers as well as primary pumps shall be sized with
COP 4.4? how can we enter the pump and cooling tower efficiency with COP4.4?<o:p></o:p></span></p>
<p class=MsoListParagraph><span style='color:navy;font-weight:normal'>Or we
just only need to input COP 4.4 for chillers while the others can use the rated
efficiency in our design?<o:p></o:p></span></p>
<p class=MsoListParagraph><span style='color:navy;font-weight:normal'><o:p> </o:p></span></p>
<p class=MsoListParagraph style='text-indent:-18.0pt;mso-list:l0 level1 lfo1'><![if !supportLists]><span
style='color:navy;font-weight:normal'><span style='mso-list:Ignore'>b)<span
style='font:7.0pt "Times New Roman"'> </span></span></span><![endif]><span
style='color:navy;font-weight:normal'>How can we input the thermal distribution
losses?<o:p></o:p></span></p>
<p class=MsoListParagraph><span style='color:navy;font-weight:normal'>What I suppose
is that, Q=mcdT, so if there are 5% thermal loss, the dT loss shall also be 5%.<o:p></o:p></span></p>
<p class=MsoListParagraph><span style='color:navy;font-weight:normal'>Does it
mean to enter 5% of design dT in the “supply loss dT” column?<o:p></o:p></span></p>
<p class=MsoListParagraph><span style='color:navy;font-weight:normal'>Or make
it simple, just multiplying 5% to the energy consumption by space cooling is
already sufficient?<o:p></o:p></span></p>
<p class=MsoListParagraph><span style='color:navy;font-weight:normal'><o:p> </o:p></span></p>
<p class=MsoNormal><span style='color:navy;font-weight:normal'>Thanks all.<o:p></o:p></span></p>
<p class=MsoNormal><span style='color:navy;font-weight:normal'><o:p> </o:p></span></p>
<p class=MsoNormal><span style='color:navy;font-weight:normal'><o:p> </o:p></span></p>
<p class=MsoNormal><span style='color:navy;font-weight:normal'><o:p> </o:p></span></p>
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<p class=MsoNormal><span style='font-size:11.0pt;font-family:"Calibri","sans-serif";
color:navy;font-weight:normal'>Best Regards,<o:p></o:p></span></p>
<p class=MsoNormal><span style='font-size:11.0pt;font-family:"Calibri","sans-serif";
color:navy;font-weight:normal'><o:p> </o:p></span></p>
<p class=MsoNormal><span style='font-size:18.0pt;font-family:"CommercialScript BT";
color:#1F497D'>Jonathan Mak<o:p></o:p></span></p>
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