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<p class=MsoNormal><span style='color:#1F497D'>Thanks! I was starting to
conclude that as well, but then I spoke to Carrier, and they said that there is
no way that it would drop off that significantly. For example, they said
they have a unit that is full load rated at .6KW/ton and .7KW/ton down to 25%
part load. The numbers I'm getting is nearing 2KW/ton, even though the
full load rating remains at .67KW/ton. I did mention that the vast
majority of my hours are operating below the 10 percent part load, but he still
said it wouldn't be that high. Any thoughts?<o:p></o:p></span></p>
<p class=MsoNormal><span style='color:#1F497D'><o:p> </o:p></span></p>
<div>
<p class=MsoNormal><span style='font-size:10.0pt;font-family:"Arial","sans-serif";
color:#1F497D'>Respectfully,</span><span style='font-size:12.0pt;font-family:
"Times New Roman","serif";color:#1F497D'><o:p></o:p></span></p>
<p class=MsoNormal><span style='font-size:12.0pt;font-family:"Times New Roman","serif";
color:#1F497D'> <o:p></o:p></span></p>
<p class=MsoNormal><span style='font-size:10.0pt;font-family:"Arial","sans-serif";
color:#1F497D'>Brett Sanicola</span><span style='font-size:12.0pt;font-family:
"Times New Roman","serif";color:#1F497D'><o:p></o:p></span></p>
<p class=MsoNormal><span style='font-size:10.0pt;font-family:"Arial","sans-serif";
color:#1F497D'>Engineer</span><span style='font-size:12.0pt;font-family:"Times New Roman","serif";
color:#1F497D'><o:p></o:p></span></p>
<p class=MsoNormal><span style='font-size:10.0pt;font-family:"Arial","sans-serif";
color:#1F497D'>ASB Engineering</span><span style='font-size:12.0pt;font-family:
"Times New Roman","serif";color:#1F497D'><o:p></o:p></span></p>
</div>
<p class=MsoNormal><span style='font-size:10.0pt;font-family:"Arial","sans-serif";
color:#1F497D'>(516) 785-4200</span><span style='color:#1F497D'><o:p></o:p></span></p>
<div>
<div style='border:none;border-top:solid #B5C4DF 1.0pt;padding:3.0pt 0in 0in 0in'>
<p class=MsoNormal><b><span style='font-size:10.0pt;font-family:"Tahoma","sans-serif"'>From:</span></b><span
style='font-size:10.0pt;font-family:"Tahoma","sans-serif"'> James Hansen
[mailto:JHANSEN@ghtltd.com] <br>
<b>Sent:</b> Thursday, April 01, 2010 4:02 PM<br>
<b>To:</b> Brett Sanicola; equest-users@lists.onebuilding.org<br>
<b>Subject:</b> RE: [Equest-users] Chiller ROI - HELP!<o:p></o:p></span></p>
</div>
</div>
<p class=MsoNormal><o:p> </o:p></p>
<p class=MsoNormal><span style='color:#1F497D'>KW/ton drops off with decreasing
part load, and since the chiller isn’t always operating at ARI full load
conditions, you can’t just divide total chiller energy consumption (in
KWH) by the total cooling load (in btu) and hope to get anywhere near the full
load rated KW/ton.<o:p></o:p></span></p>
<p class=MsoNormal><span style='color:#1F497D'><o:p> </o:p></span></p>
<p class=MsoNormal><span style='color:#1F497D'>As you go about this ROI study,
make sure that when you are analyzing your proposed chiller replacement, that
you create a custom EIR vs PLR curve based on manufacturer’s data,
otherwise you’re using a default DOE-2 curve that isn’t necessarily
correct.<o:p></o:p></span></p>
<p class=MsoNormal><span style='color:#1F497D'><o:p> </o:p></span></p>
<p class=MsoNormal><span style='color:#1F497D'>Furthermore, to make the study
worthwhile, the existing chiller model really needs to be normalized as best as
possible to actual building operating conditions. You can get away
without doing it for a simple comparison, but it would be more accurate if you
normalized to utility bills.<o:p></o:p></span></p>
<p class=MsoNormal><span style='color:#1F497D'><o:p> </o:p></span></p>
<div>
<p class=MsoNormal><b><span style='font-family:"Arial","sans-serif";color:teal'>GHT
Limited<br>
</span></b><b><span style='font-family:"Arial","sans-serif"'><ns0:PersonName><span
style='color:black'>James Hansen</span></ns0:PersonName></span><span
style='color:black'>, PE, LEED AP<o:p></o:p></span></b></p>
<p class=MsoNormal><b><span style='font-size:10.0pt;font-family:"Arial","sans-serif";
color:black'>Senior Associate</span><span style='color:black'><o:p></o:p></span></b></p>
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style='color:black'>VA</span></ns0:State><span style='color:black'> </span><ns0:PostalCode><span
style='color:black'>22201-4749</span></ns0:PostalCode></ns0:place></span><span
style='color:black'><o:p></o:p></span></p>
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href="http://www.ghtltd.com/"><span style='font-size:10.0pt'>www.ghtltd.com</span></a><o:p></o:p></span></p>
<p class=MsoNormal><b><span style='color:#31849B'><o:p> </o:p></span></b></p>
</div>
<p class=MsoNormal><span style='color:#1F497D'><o:p> </o:p></span></p>
<div>
<div style='border:none;border-top:solid #B5C4DF 1.0pt;padding:3.0pt 0in 0in 0in'>
<p class=MsoNormal><b><span style='font-size:10.0pt;font-family:"Tahoma","sans-serif"'>From:</span></b><span
style='font-size:10.0pt;font-family:"Tahoma","sans-serif"'>
equest-users-bounces@lists.onebuilding.org
[mailto:equest-users-bounces@lists.onebuilding.org] <b>On Behalf Of </b>Brett
Sanicola<br>
<b>Sent:</b> Thursday, April 01, 2010 2:38 PM<br>
<b>To:</b> equest-users@lists.onebuilding.org<br>
<b>Subject:</b> [Equest-users] Chiller ROI - HELP!<o:p></o:p></span></p>
</div>
</div>
<p class=MsoNormal><o:p> </o:p></p>
<p class=MsoNormal>I've been attempting to calculate a simple ROI for a new 250
ton chiller our client wants to install to replace his older chiller. I
ran the simulation for the default "high rise hotel" construction
which, to my luck, is quite similar to the actual building. The detailed
results, however, are not making sense to me. Specifically, when I look
at Equipment Loads and Energy Use for the Chiller, the Elec Use and Cool Load
don't coincide given the default Chiller efficiency of .67kw/ton. For
example they give a Chiller Elec Use of 535453 KWH and a Cool Load of 3294
MBTU. However, according to my calculations, at .67KW/TON, 535453 KWH
should give me closer to 9590 MBTU. I see most of the hours are in part load
range, but does the efficiency drop off that dramatically at part load that it
would explain the discrepancy? Which numbers should I base my analysis
on, the Cool Load number or the Elec Use number.<o:p></o:p></p>
<p class=MsoNormal> <o:p></o:p></p>
<p class=MsoNormal>Also, on the same page (Equipment Loads and Energy Usage),
it gives me a peak load of 2436 KBTU/HR. However, when I go to the
section titled "Building Peak Load Components" the peak cooling load
is significantly less (1619 KBTU/HR)<o:p></o:p></p>
<p class=MsoNormal> <o:p></o:p></p>
<p class=MsoNormal>At this point, I have no idea what any number represents,
since I don’t know how it was calculated.<o:p></o:p></p>
<p class=MsoNormal> <o:p></o:p></p>
<p class=MsoNormal>I greatly appreciate any help! Thanks.<o:p></o:p></p>
<p class=MsoNormal> <o:p></o:p></p>
<p class=MsoNormal><span style='font-size:10.0pt;font-family:"Arial","sans-serif"'>Respectfully,</span><o:p></o:p></p>
<p class=MsoNormal><span style='font-size:12.0pt;font-family:"Times New Roman","serif"'> </span><o:p></o:p></p>
<p class=MsoNormal><span style='font-size:10.0pt;font-family:"Arial","sans-serif"'>Brett
Sanicola</span><o:p></o:p></p>
<p class=MsoNormal><span style='font-size:10.0pt;font-family:"Arial","sans-serif"'>Engineer</span><o:p></o:p></p>
<p class=MsoNormal><span style='font-size:10.0pt;font-family:"Arial","sans-serif"'>ASB
Engineering</span><o:p></o:p></p>
<p class=MsoNormal><span style='font-size:10.0pt;font-family:"Arial","sans-serif"'>(516)
785-4200</span><o:p></o:p></p>
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