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<DIV><FONT face=Arial size=2><SPAN class=345183020-16092009>eQuesters &
DOE2-2ers,</SPAN></FONT></DIV>
<DIV><FONT face=Arial size=2><SPAN
class=345183020-16092009></SPAN></FONT> </DIV>
<DIV><FONT face=Arial size=2><SPAN class=345183020-16092009>
The DOE2-2 dictionary loves to use the phrase, "total fan power per unit flow"
in defining SUPPLY-KW/FLOW. Clear as mud.</SPAN></FONT></DIV>
<DIV><FONT face=Arial size=2><SPAN class=345183020-16092009> I
figured this: At design conditions, the supply fan runs at 9.90 BHP and
61.89% efficiency and the per-unit flow is at unity ( x CFM / x CFM = 1).
The motor nominal efficiency is 93%. (No, I don't have a motor efficiency
curve.) 0.746 kW = 1 HP. Therefore, the fan kW =
9.90 * 0.746 / ( 0.6189 * 0.93 ) = 12.83 kW. The per unit flow
is 1. So... SUPPLY-KW/FLOW = 12.83, which I type into my .inp
file.</SPAN></FONT></DIV>
<DIV><FONT face=Arial size=2><SPAN class=345183020-16092009>
Naturally, eQuest gives me an error message, insisting that SUPPLY-KW/FLOW must
be between 0.0 and .0080. Evidently, there is some discrepancy involving
units or the meaning of "per unit" in the context of the quoted
phrase.</SPAN></FONT></DIV>
<DIV><FONT face=Arial size=2><SPAN class=345183020-16092009>
Can anyone clarify what eQuest really means and how to calculate
SUPPLY-KW/FLOW? Is it supposed to be KW-per-CFM?</SPAN></FONT></DIV>
<DIV><FONT face=Arial size=2><SPAN class=345183020-16092009>
Thanks!</SPAN></FONT></DIV>
<DIV><FONT face=Arial size=2><SPAN
class=345183020-16092009></SPAN></FONT> </DIV>
<DIV><FONT face=Arial size=2><SPAN class=345183020-16092009>Lars Fetzek,
EI</SPAN></FONT></DIV>
<DIV><FONT face=Arial size=2><SPAN class=345183020-16092009>Phoenix Engineering
Group</SPAN></FONT></DIV>
<DIV><FONT face=Arial size=2><SPAN class=345183020-16092009>Tampa,
Florida</SPAN></FONT></DIV></BODY></HTML>