[Equest-users] Elevator Loads

[Sharad Kumar via Equest-users]

Hi Darryl,

As we know that power has a formula of power is equal to force into velocity.
Hence if one applies the pound (lbs) multiplied with 0.454 kg (kg=lbs
* 0.454  ) to get the mass in kg.
Then if we get velocity which is in fpm to m/s. (m/s= fpm/ 3.28/ 60)
Then we are required to multiply the mass (which is same as force) and
velocity to get the power which is coming as 4.037 kW and 6.459 kW in
my case.
Hope this may help.


Thanks,
Sharad.


---------- Forwarded message ----------
From: Darryl Kasun via Equest-users <equest-users at lists.onebuilding.org>
To: equest <equest-users at lists.onebuilding.org>
Cc:
Date: Tue, 11 Oct 2016 20:44:14 -0700
Subject: [Equest-users] Elevator Loads

Hi everyone,

I would like to model some elevators.  I have the following info on
the elevators:

- Elevators 1, 2, 3, 4 & 5:  5000 lbs ea; 350 fpm.
- Elevators 6 & 7:  14,000 lbs ea; 200 fpm.

Does anyone know a rough load (ie. kW) that I can apply to these elevators?

Thanks
Darryl