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<DIV><FONT face=Verdana size=2><SPAN class=738392023-06102006>I am using eQuest,
and</SPAN></FONT><FONT face=Verdana size=2><SPAN class=738392023-06102006>
am modeling a building with a ground source heat pump (open loop) and
heat recovery chiller. In eQuest, I have a </SPAN></FONT><FONT
face=Verdana size=2><SPAN class=738392023-06102006>ground-water circulation loop
(open lake/well type), and am using a Loop-to-Loop heat pump chiller.
<SPAN class=738392023-06102006>I am looking at two scenarios: a constant
condenser water temperature (well water at 55°F all year), and a varying
condenser water temperature (well water winter temp low at 51°F, and summer temp
high at 63°F, and a curve fit varying the water in between). I already have
schedules set up to simulate the condenser water temperature
scenarios this, but am running into problems in determining how the chiller
performance curves are working...</SPAN></SPAN></FONT></DIV>
<DIV><FONT face=Verdana size=2><SPAN class=738392023-06102006><SPAN
class=738392023-06102006></SPAN></SPAN></FONT> </DIV>
<DIV><FONT face=Verdana size=2><SPAN class=738392023-06102006><SPAN
class=738392023-06102006></SPAN>Does anyone out there have an understanding of
the relationship of the various doe2 default EIR and performance curves for
this loop-to-loop heat pump chiller type (operating in both cooling and heating
mode).... I'm not finding a lot of direction in the doe.2
dictionary. </SPAN></FONT><FONT face=Verdana size=2><SPAN
class=738392023-06102006>I would like to ask a chiller manufacturer to provide
part-load curves and EIRs at different condenser water temperatures, but cannot
tell how these values are translated into the three performance curves indicated
for this chiller.</SPAN></FONT></DIV>
<DIV><FONT face=Verdana size=2><SPAN
class=738392023-06102006></SPAN></FONT> </DIV>
<DIV><FONT face=Verdana size=2><SPAN class=738392023-06102006>I have
generated performance curves in the past for condensing boilers, and part load
curves for centrifugal chillers, so I already understand the general principle
of normalizing the data. </SPAN></FONT></DIV>
<DIV><FONT face=Verdana size=2><SPAN
class=738392023-06102006></SPAN></FONT> </DIV>
<DIV><FONT face=Verdana size=2><SPAN class=738392023-06102006>Any help you
could offer would be much appreciated.</SPAN></FONT></DIV>
<DIV><FONT face=Verdana size=2><SPAN
class=738392023-06102006></SPAN></FONT> </DIV>
<DIV><FONT face=Verdana size=2><SPAN class=738392023-06102006>Thank
you,<BR>Kate</SPAN></FONT></DIV><PRE>
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