[Equest-users] FW: Cooling EIR and unit EER

[Kathryn Kerns]

Does anyone know if the EER to EIR conversion mentioned below applies to
chiller COP values? For instance, if chiller data lists a full load
efficiency of COP 3.1/EER 10.5, do we then apply the EIR conversion and
enter that into the eQuest chiller EIR space?

 

Also, does anyone have a way of extrapolating a partial load curve for
any cooling equipment that lists a full load EER and an IPLV EER? The
equation for IPLV is:

IPLV = 0.01A 0.42B 0.45C 0.12D 

where

A = COP at 100% load and an ECWT of (85F)

B = COP at 75% load and an ECWT of (75F)

C = COP at 50% load and an ECWT of (65F)

D = COP at 25% load and an ECWT of (65F)

 

Unfortunately, I think I have too many variables and not enough data

 

 

 

Kathryn Kerns

Systems Specialist

BCE Engineers, Inc.

| Ph: 253.922.0446 | Fx: 253.922.0896 | 

 

 

 

________________________________

From: equest-users-bounces at lists.onebuilding.org
[mailto:equest-users-bounces at lists.onebuilding.org] On Behalf Of Supriya
Goel
Sent: Wednesday, January 13, 2010 5:13 PM
To: Katie Tuttle
Cc: equest-users at lists.onebuilding.org
Subject: Re: [Equest-users] Cooling EIR and unit EER

 


Hello

 

I've attached the document. Though it is nothing more than a sheet out
of our assignment for the eQuest class.

I do not have the original document from where this would have been
taken. Hopefully this helps :)

 

Regards

Supriya

 

On Wed, Jan 13, 2010 at 4:28 PM, Katie Tuttle <Katie.Tuttle at hei-eng.com>
wrote:

I would be curious to see that document.  Would you mind posting it?
Thanks!

 

From: equest-users-bounces at lists.onebuilding.org [mailto:
equest-users-bounces at lists.onebuilding.org] On Behalf Of Supriya Goel
Sent: Wednesday, January 13, 2010 5:22 PM
To: Jacob Goodman
Cc: equest-users at lists.onebuilding.org
Subject: Re: [Equest-users] Cooling EIR and unit EER

 

Jacob

 

You're right, EIR is not equal to 1/(EER/3.14)

 

The equation used by eQuest for calculating EIR from EER is-

 

COOLING-EIR = (1/EER - 0.012167) / ((1 / 3.413) + 0.012167)

 

If you want more information, I could send you the document from where I
got this.

 

Regards

Supriya

 

On Wed, Jan 13, 2010 at 4:11 PM, Jacob Goodman <jacobg at lseng.com> wrote:

How does eQuest calculate "cooling electrical input ratio" shown in
detailed edit mode when you input an EER in the wizard? >From a few
checks I've done cooling EIR doesn't equal 1/(EER/3.413) as I would
expect.


Jacob 

 


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Arizona State University, Tempe

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